Question

As illustrated in the figure, a spring with spring constant k is stretched from =0 to x = 3d, where x = 0 is the equilibrium position of the spring. (Figure 1) Figure WA MW x= x=2d X = 3/ x= Equilibrium position

   Now consider 2 Springs A and B that are attached to a wall. Spring A has a Spring constant that is 4 times that of the Spring constant up Spring be. If the same amount of energy is pro choir to stretch both Springs, what can be said about the distance each Spring is stretched?

Answer 1

Energy required to Shelch, Spring by a tharing Spring constant is ti distance U= 12 kn 2 4k .: VAS UB (aiven) Ž (46) XA² = { K 43² x3 = 4x 7 Mo = 2x4] ® *= *8 = 2XA spring A must stretch half the distance spring stretche

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