The statistical software output for this problem is :
The 95% CI is :
-4.7 1.0
plz answer asap Assume that the paired data came from a population that is normally distributed....
Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d =x-y find d, sd, the t test statistic, and the critical values to test the claim that ?d-0 10 12 17 6 6 13 12 6 6 d | (Round to three decimal places as needed.) Sd(Round to three decimal places as needed.) t (Round to three decimal places as needed.) t(Round to three decimal places as needed.) a/2
Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d=x−y, find _ d, sd, the t test statistic, and the critical values to test the claim that μd=0. x 13 7 8 6 6 14 8 9 y 13 7 5 5 6 9 9 12 _ d= (Round to three decimal places as needed.) sd= (Round to three decimal places as needed.) t= (Round to three decimal places...
assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d=x-y, find d, sd, the t test statistic, and the critical values to test the claim that d=0. x 11 19 7 19 12 7 2 6 and y 10 15 6 14 7 6 7 5 K over ch 8,9, 10 GRADED 10 15
Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d equals=x minus??y, find d overbard?, s Subscript dsd?, the t test? statistic, and the critical values to test the claim that mu Subscript d?dequals=0. x 7 1 6 9 6 10 6 11 y 5 6 8 14 8 12 8 12 d overbardequals= ?(Round to three decimal places as? needed.) s Subscript dsdequals= ?(Round to three decimal places as?...
1 2 In a survey, 28% of 215 single women said that they "definitely want to have children." In the same survey, 22% of 295 single men gave the same response. Construct a 90% confidence interval estimate of the difference between the proportions of single women and single men who definitely want to have children. Is there a gender gap? Construct a 90% confidence interval estimate. D- <p1-p2 <L (Round to three decimal places as needed.) Is there a gender...
please display the answer in clear decimal format Assuming that the population is normally distributed, construct a 95% confidence interval for the population mean, based on the following sample size of n = 7. 1, 2, 3, 4, 5, 6, and 15 In the given data, replace the value 15 with 7 and recalculate the confidence interval. Using these results, describe the effect of an outlier (that is, an extreme value) on the confidence interval, in general. Find a 95%...
Assuming that the population is normally distributed, construct a 95% confidence interval for the population mean, based on the following sample size of .n=7. 1, 2, 3, 4, 5, 6, and 15 <-----this is the data In the given data, replace the value 15 with 7 and recalculate the confidence interval. Using these results, describe the effect of an outlier (that is, an extreme value) on the confidence interval, in general. Find a 95% confidence interval for the population mean,...
simple random sample of size n is drawn from a population that is normally distributed. The sample mean, X. is found to be 111, and the sample standard deviation is found to be 10. a) Construct a 95% confidence interval about if the sample size, n, is 28. b) Construct a 95% confidence interval about if the sample size, n, is 11 c) Construct a 90% confidence interval about if the sample size, n, is 28 ) Could we have...
A simple random sample of size nis drawn from a population that is normally distributed the sample mean is found to be 113, and the sample standard deviations, is found to be 10 (a) Construct a 95% confidence interval about if the sample size is 22 (b) Construct a 95% confidence interval about the sample on 26 (c) Construct a 90% confidence interval about the sample size is 22 (d) Could we have computed the confidence intervals in parts(a-c) if...
A simple random sample of size n=20 is drawn from a population that is normally distributed with o = 11. The sample mean is found to be x = 59. Construct a 95% confidence interval about the population mean. The 95% confidence interval is . (Use ascending order. Round to two decimal places as needed.)