Question

2. Complete the following acid/base equation, filling in all missing details: missing lone pairs, curved arrows to show electron move and proper formal charge. If there are any resonance structures draw them as well One acid has a pka of 5 and the other acid has a pKa of 15. Match each pka with the proper acid (write it under the acid). Which side is favored and why? Calculate an equilibrium constant (Kog) for the reaction.

Answer 1

H. H H Tauto marismo H, C S8: : Z Acetate Ion - н, .. Н . :Z- u 8 = o CH3 *3 Acetamide - Ra 10-5. for acetic acid = CHg coi le 1 pka = 5 I - Ka for CH₂ CONHg = 10-15 pka = 15 T 1 Stronger the acid higher the ka ralue Lower the pka value Stronger acid will donate proton (Hit) and weaker acid will accept proton. Stronger acid will form weaker Conjugate base. weaker and will form stronger Conjugate base. ... → -

Strong react acid and to form strong bare will always 3 weaker acid and weaken base. CH3CNH - CH₂ Coo- THE (Strong acid) pka = 5 I weak . Conjugate base -C-NH HⓇ + CHE CONHO Strong Conjugate base. 0-H CENH pka=15 weak acid) :o: CH3-C EN-Hit CH3 -C-0-1 a pka= 5 CHE Ka = 10-5 It | . . . CH3-c= –H pka = 15 oto D en 10-15 H-I5 = b itiwiteiten Product side is faroured. (weak acid and weak a conjugate base is formed). Please write in Comment box for forthur clarification.