Question

33 EXERCISE PROBLEM Ex 3.6: Consider the circuit shown in Figure 3.30. The nominal transistor parameters are Vrp = -0.30 V and K, = 120 u A/V2. (a) Calculate Vsg, Ip. and VSD. (b) Determine the variation in Ip if the threshold voltage varies by £5 percent. (Ans. (a) Vsg = 1.631 V, Ip = 0.2126 mA, VSD = 3.295 V; (b) 0.2091 < Ip < 0.2160 mA)

Answer 1

+2.2V Given R = 25563 & Rs = 6ks Vpp = -0.30 v Kp = 120 m Alu- Vsa t VSD 6 =3458 Ro=42ke -2.2V the Assumption first Region, is MOSFET is in saturation Then Rith 2 IP kp (Vsa + Vp ) ² Vesa NDD - Vsa - Va=0 ~ By Applying kuh | Vsa = Vpp-va Va is the Thevinin, voltage Nu = VDD A R2 ( 2.27 2. 2) x 345 0 0 345+255 12650 Vsa = 2,2- 1885-8925 2.2 ID = 120 x (875 -0.50) = 48 147mA 43IMA kV at Outerloop van twee - 2/2 & 8X ID & VD A 4 2 X ID D + 28 = 0 Vpp = 6 ID + G2ID = htID = $320.79 The Assumption is saturation Neo 3 Vol Sad) i Vsa + Vap 0.955 -0.3 = 0.635 2.2

20898 0.639 so the moIFET in saturation region,