Question

Chapter 26A Homem Christopher Cooper e-PHY 122 - Summer 19 - HAN Activities and Due Dates Chapter 26A Homework gnment Score: 1145/1500 Resources Hint Check Answe stion 8 of 15 > Exitance is defined as the power per unit area that is emitted from the surface of an object. For a blackbody radiator, the exitance emitted is dependent upon its temperature. Calculate the exitance in W/cm' for a blackbody radiator at 69 K and 328 K. exitance at 69 K = W/cm exitance at 328 K = W/cm2 about us career privacy policy terms of use contact us

Answer 1

We know power radiated PJATY for blackbody e=1 So when T=69K F ret" but A is in m? to change it into con? we need to divide LHS & RHS with (2007? so, Exitance = = 104 At 69K Exitance to poi = 1.285 x1024 w/cm? Hence Exitance : 1.285x 10" when? Similarly at 328k Bxitana = 5-67*320" - 0.08563 Exitance. = 5-67 X 328 - 0.0656 cm 1012