Find Percent Error Initial length Ll ) Initial Final micrometer micrometer setting setting Initial temp. T.6°C...

Question

Question

Answer 1

Answer #1

Copper:

Percent error in $\alpha$ is 100 = Olaccepted - Omeasured Oaccepted 16.8 * 10-6 – 15.7 * 10-6 — * 100 = 6.55% 16.8 * 10-6

Brass:

Percent error in $\alpha$ is Caccepted - Omeasured Oaccepted 18.8 * 10-6 – 18.75 * 10-6 – * 100 = 2.78% 18.8 * 10-6

Aluminium:

Percent error in $\alpha$ is 100 Qaccepted -- Omeasured Oaccepted 24.0 * 10-6 - 23.48 * 10-6 - * 100 = 2.22% 24.0 * 10-6

Answer 2

Similar Homework Help Questions

Initial Initial Final Initial length micrometer micrometer Delta temp Final Delta alpha alpha (m) setting setting...

Initial Initial Final Initial length micrometer micrometer Delta temp Final Delta alpha alpha (m) setting setting IL temp T (measured) (theory) Aluminum 0.63 0 0.91 mm 24.1 100 24x10-6 Copper 0.64 0 0.78 mm 23.1 100 16.8 Steel 0.61 0 0.53 mm 24.7 100 13.4 Theory: L(T)=Lo (1+ a(T-To); A T=T-T o; A L=L-LO 1. Alfa Ameas= A L/L AT 2. Percent Error %=[ (ath- Am)/ ath] 100% 3. Alfa copper=16.8 x10-6(1/C) 4. Alfa steel =13.4 x10-6 (1/C) 5. Alfa...
what are the probable sources of error in this experiment? which will cause the Date Section...

what are the probable sources of error in this experiment? which will cause the Date Section dah Partnents) EX PERIMENT 1 6 The Thermal Coefficient of Linear Expansion TLaboratory Report DATA TABLE Purpose: To determine the thermal coefficients of expansion of metal samples. Initial Final Initial micrometer micrometer Initial Final accepted meas length temp. T AT temp. T AL setting setting 1. Type of rod 2. Туре оf rоd 3. Type of rod Calculations (show work) Metal Percent error Don't...