Consider reaction, SiO2 (s) + 4 HCl (g) SiCl 4 (g) + 2 H2O (g)
We can calculate H0 rxn by using equation, H0 rxn = H 0 f ( products ) - H 0 f ( reactants )
Let's calculate H 0 f (products) and H 0 f (reactants) .
H 0 f (products) = H 0 fSiCl 4 (g) + 2 H 0 f H2O (g)
H 0 f (products) = (- 662.8 kJ mol -1 ) + 2 ( - 241.8 kJ mol -1 )
H 0 f (products) = - 1146.4 kJ mol -1
H 0 f ( reactants ) = H 0 f SiO2 (s) + 4 H 0 f HCl (g)
H 0 f ( reactants ) = (- 859.2 kJ mol -1 ) + 4 ( -92.3 kJ mol -1 )
H 0 f ( reactants ) = (- 859.2 kJ mol -1 ) - 369.2 kJ mol -1
H 0 f ( reactants ) = - 1228.4 kJ mol -1
H0 rxn = - 1146.4 kJ mol -1- ( - 1228.4 kJ mol -1)
H0 rxn = 82.0 k J / mol
ANSWER : H0 rxn = 82.0 k J / mol
Ch. 5, 6 A What is AH rxn for the following reaction? SIO2 (s) + 4HCl(g)...
Hess's Law Practice Find AH° for the following equation: SiO2(s) + 4HF(g) → SiF4(g) + 2H2O(g) Using the following equations: Si(s) + O2(g) → SiO2(s) Si(s) + 2F2(g) → SiF4(g) H2(g) + F2(g) → 2HF(g) H2(g) + 4202(g) → H2O(g) AH = -910.9 kJ/mol rxn AH = -1651 kJ/mol rxn AH = -542 kJ/mol rxn AH = -241.8 kJ/mol rxn
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