Question

Question#03: Input an integer containing only Os and is (i.e., a "binary" integer) and print its decimal equivalent. (Hint: Use the remainder and division operators to pick off the "binary number's digits one at a time from right to left. Just as in the decimal number system, in which the rightmost digit has a positional value of 1, and the next digit left has a positional value of 10, then 100, then 1000, and so on, in the binary number system the rightmost digit has a positional value of 1, the next digit left has a positional value of 2, then 4, then 8, and so on. Thus the decimal number 234 can be interpreted as 4* 1 + 3 * 10 + 2 * 100. The decimal equivalent of binary 1101 is 1 * 1 + 0*2 +1 * 4+1 * 8 or 1 + 0 + 4 + 8 or 13.)

Answer 1

THE PROGRAM IS DONE WITH JAVA AND C++

PROGRAM IN JAVA

/* import scanner class from util package */
import java.util.Scanner;
import java.lang.Math;

class bin_decimal
{

int binary_decimal(int b)
{
   
   int i=0;
   int s=0,a;
   while(b!=0)
{
       a=b%10;
       s=s+(int)(Math.pow(2,i)*a);
       b=b/10;
       System.out.println(b);
       i++;
    }  
    return s;
}
  
}
public class convert
{
public static void main(String[] args)
{
   int bin,res;
   /* sc object of scanner class */
   Scanner sc=new Scanner(System.in);
   /* ob object of bin_decimal class */
bin_decimal ob=new bin_decimal();
   System.out.println();
   System.out.print("Enter a binary number :");
   bin=sc.nextInt();
   res=ob.binary_decimal(bin);
   System.out.println("\nDecimal equivalant of binary " + bin + " is : " + res);
}
}

SCREEN SHOT

/* import scanner class from util package */ import java.util.Scanner; import java.lang.Math; class bin_decimal int binary_decimal (int b) int i=0; int 3=0, a; while (b!=0) a=b010; 9=3+(int) (Math.pow (2,1) *a); b=b/10; System.out.println(b); i++; return 3; public class convert public static void main(String[] args) int bin, res; /* object of scanner class */ Scanner sc=new Scanner (System.in); /* ob object of bin_decimal class */ bin_decimal ob=new bin_decimal();

System.out.println(); System.out.print ("Enter a binary number :"); bin=sc.nextInt (); res=ob.binary_decimal (bin); System.out.println("\nDecimal equivatante of binary " + bin + " is : " + res) ;

OUTPUT

C:\Program Files\Java\jdk1.8.0_131\bin>javac convert.java C:\Program Files\Java\jdk1.8.0_131bin>java convert Enter a binary number :1100 110 11 Decimal equivalant of binary 1100 is : 12

PROGRAM IN C++

#include<iostream>
#include<math.h>
using namespace std;

int binary_decimal(int b)
{
   
   int i=0,s=0,a;
   while(b!=0)
{
       a=b%10;
       s=s+(pow(2,i)*a);
       b=b/10;
       i++;
    }  
    return s;
}
main()
{
   int bin,dec,i=0,s=0,a,b,res;
   cout<<"Enter a binary number :";
   cin>>bin;
   res=binary_decimal(bin);
   cout<<"\nDecimal equivalant of binary "<<bin<<" is : "<<res;
}

SCREEN SHOT

#include<iostream> #include<math.h> using namespace std; int binary_decimal(int b) int i=0,s=@,a; while(b!=0) a=b%10; S=5+(pow (2,i)*a); b=b/10; i++; return s; main() int bin, dec, i=0,s=0, a, b,res; cout<<"Enter a binary number :"; cin>>bin; res=binary_decimal(bin); cout<<"\nDecimal equivalant of binary "<<bin<<" is : "<<res;

OUTPUT

C:\Users\cse\Documents\bin_dec.exe Enter a binary number :1100 Decimal equivalant of binary 1100 is : 12 Process exited after 3.422 seconds with return value o Press any key to continue ...