Question

etermine the voltage and current of each of the elements in the circu power delivered by each current source. 1.5A V4 0.5A 30V v1 1200 +V3 20Ω

Answer 1

30V_9 120 ohm are parallel rightarrow In parallel, voltage remains same therefore V_1 = 30V therefore L_1 = V_1/120 = 30/120 = 0.25 A from circuit (node 'a') 1.5A + 0.5A = i_2 therefore i_2 = 2A V_2 = (40 ohm) (2A) = 80V similarly 40 ohm, 0.5A are parallel therefore V_6 = V_2 = 80V. \r\n from circuit (node 'c') i_5 = i_1 + 1.5A therefore i_5 = 0.25A + 1.5A = 1.75A similarly (node 'b') i_2 = i_3 + 0.5A therefore i_3 = i_2 - 0.5 = 1.5A therefore i_3 = 1.5A V_3 = -i_3 (20 ohm) = -1.5 times 20 = 30V Apply KVL in middle loop -V_1 + V_4 + V_2 - V_3 = 0 therefore V_4 = V_1 + V_3 - V_2 V_4 = 30 - 30 - 80 therefore V_4 = -80V power delivered by 1.5A current source p_1.5A = V_4 (1.5A) = 80 times 1.5 = p_1.5A = 120 walts delivered. \r\n power delivered by 0.5A source p_0.5A