Homework Answers
What are the hybridizations of the three labeled atoms? :0: D (-=- :0: -H:0: H H....
What are the hybridizations of the three labeled atoms? :0: D (-=- :0: -H:0: H H. -Η 10 O=0 B н. C H H A) 1=sp?, 2=sp?, 3-sp3 B) 1=sp2, 2=sp3, 3=sp2 C) 1=sp3, 2=sp3, 3=sp3 D) 1-sp3, 2=sp3, 3=sp? E) 1=sp, 2-sp?, 3=sp? ОА OB OC OD OE
What are the hybridizations of the three labeled atoms? :0: 0-H:0: H н. CH 오g C...
What are the hybridizations of the three labeled atoms? :0: 0-H:0: H н. CH 오g C H - H H A) 1=sp?, 2=sp2, 3=sp3 B) 1=sp?, 2=sp3, 3=sp? C) 1=sp3, 2=sp3, 3=sp3 D) 1=sp?, 2-spº. 3=sp? E) 1=sp, 2=sp2, 3=sp? OA B OC OD
What are the correct hybridizations of the indicated atoms in the following molecules. A. 1, sp3:2,...
What are the correct hybridizations of the indicated atoms in the following molecules. A. 1, sp3:2, sp3: 3, sp; 4, sp3 B. 1, sp2: 2, sp3 ; 3, sp2 : 4, sp2 C. 1. sp3; 2. sp3: 3, sp3, 4, sp3 D. 1, sp3: 2, sp: 3, sp2: 4, sp3 E 1, sp2: 2, sp3; 3, sp; 4, sp3
6. Carbon atoms with sp hybridization have a _____ molecular geometry. Group of answer choices Linear...
6. Carbon atoms with sp hybridization have a _____ molecular geometry. Group of answer choices Linear Trigonal planar Tetrahedral Bent 7. Saturated hydrocarbons (alkanes) have what hybridization at every carbon atom? sp3 sp2 sp They have several different orbital hybridizations. 8. Conjugated dienes must have which of the following orbital hybridizations? Group of answer choices sp3 sp2 sp sp3d2 9. Alkynes must have which of the following orbital hybridizations? Group of answer choices sp3 sp2 sp None of these answers...
Question 5 1 pts Which bond(s) allow(s) free rotation? Select ALL that apply. H H :0: 2 H=C=c———0 CH Bond 3 Bond 1 Bond...
Question 5 1 pts Which bond(s) allow(s) free rotation? Select ALL that apply. H H :0: 2 H=C=c———0 CH Bond 3 Bond 1 Bond 2 Question 4 1 pts What are the hybridizations of atoms 1, 2, and 3, respectively in the structure below? 10: C2 sp2 sp2 03 sp sp sp spº sp sp2 sp sp3 ОЕ OD
Please answer & explain 6-9 Select the correct molecular geometry of the left-most and right-most carbon...
Please answer & explain 6-9
Select the correct molecular geometry of the left-most and right-most carbon atom in the molecule below. Left-most carbon Right-most carbon trigonal planar linear нссо —н tetrahedral trigonal pyramidal tetrahedral trigonal planar trigonal pyramidal linear What is the bond angle for atoms in a molecule consisting of 2 bonding domains and 2 nonbonding domains? 120° c) 109.5° 180° 8. Select the correctly identified bond angles indicated in the structure below. Η Hii 180° H-C-C=C—C=N 90° 180°...
Question 4 1 pts Which of the lists of increasing ionic radii is not correct? A)...
Question 4 1 pts Which of the lists of increasing ionic radii is not correct? A) CI° < Br< 1 B) A13+ < Mg2+ < Nat C) Ca2+ < Sr2+ < Ba2+ D) 52- < Cl" <k E) Nat < 02- < N3- ОА B Ос D О Е What are the hybridizations of the three labeled atoms? :0: -0-H:0: H 5(-- cec H ö -C-C-H B C С C H А H A) 1=sp?, 2=sp?, 3=sp3 B) 1=sp?, 2=sp3,...
What are the hybridizations of atoms 1, 2, and 3, respectively in the structure below? N1...
What are the hybridizations of atoms 1, 2, and 3, respectively in the structure below? N1 C2 O3 A) sp3 sp2 sp B) sp3 sp sp2 C) sp3 sp sp3 D) sp2 sp sp E) sp2 sp2 sp3 Н O 1 3 (2 Н—N—С С—С ЕС- -о—Н -
What is the correct order of hybridization state for the numbered carbon atoms in the following...
What is the correct order of hybridization state for the
numbered carbon atoms in the following compound?
I = sp, II = sp2, III = sp3
I = sp3, II = sp2, III = sp
I = sp, II = sp2, III = sp
I = sp2, II = sp3, III = sp2
I = sp2, II = sp, III = sp2
HH H C H H C H C H H H
In carbon disulfide, CS2 (carbon is the central atom), the hybridization at carbon and approximate S–C–S...
In carbon disulfide, CS2 (carbon is the central atom), the hybridization at carbon and approximate S–C–S bond angle are, respectively, A. sp2 and 120° B. sp3 and 109.5° C. sp and 180° D. sp and 120° E. sp2 and 109.5° F. none of these answers is correct
What are the hybridizations of the three labeled atoms? :0: D (-=- :0: -H:0: H H. -Η 10 O=0 B н. C H H A) 1=sp?, 2=sp?, 3-sp3 B) 1=sp2, 2=sp3, 3=sp2 C) 1=sp3, 2=sp3, 3=sp3 D) 1-sp3, 2=sp3, 3=sp? E) 1=sp, 2-sp?, 3=sp? ОА OB OC OD OE
What are the hybridizations of the three labeled atoms? :0: 0-H:0: H н. CH 오g C H - H H A) 1=sp?, 2=sp2, 3=sp3 B) 1=sp?, 2=sp3, 3=sp? C) 1=sp3, 2=sp3, 3=sp3 D) 1=sp?, 2-spº. 3=sp? E) 1=sp, 2=sp2, 3=sp? OA B OC OD
What are the correct hybridizations of the indicated atoms in the following molecules. A. 1, sp3:2, sp3: 3, sp; 4, sp3 B. 1, sp2: 2, sp3 ; 3, sp2 : 4, sp2 C. 1. sp3; 2. sp3: 3, sp3, 4, sp3 D. 1, sp3: 2, sp: 3, sp2: 4, sp3 E 1, sp2: 2, sp3; 3, sp; 4, sp3
Question 5 1 pts Which bond(s) allow(s) free rotation? Select ALL that apply. H H :0: 2 H=C=c———0 CH Bond 3 Bond 1 Bond 2 Question 4 1 pts What are the hybridizations of atoms 1, 2, and 3, respectively in the structure below? 10: C2 sp2 sp2 03 sp sp sp spº sp sp2 sp sp3 ОЕ OD
Please answer & explain 6-9
Select the correct molecular geometry of the left-most and right-most carbon atom in the molecule below. Left-most carbon Right-most carbon trigonal planar linear нссо —н tetrahedral trigonal pyramidal tetrahedral trigonal planar trigonal pyramidal linear What is the bond angle for atoms in a molecule consisting of 2 bonding domains and 2 nonbonding domains? 120° c) 109.5° 180° 8. Select the correctly identified bond angles indicated in the structure below. Η Hii 180° H-C-C=C—C=N 90° 180°...
Question 4 1 pts Which of the lists of increasing ionic radii is not correct? A) CI° < Br< 1 B) A13+ < Mg2+ < Nat C) Ca2+ < Sr2+ < Ba2+ D) 52- < Cl" <k E) Nat < 02- < N3- ОА B Ос D О Е What are the hybridizations of the three labeled atoms? :0: -0-H:0: H 5(-- cec H ö -C-C-H B C С C H А H A) 1=sp?, 2=sp?, 3=sp3 B) 1=sp?, 2=sp3,...
What is the correct order of hybridization state for the
numbered carbon atoms in the following compound?
I = sp, II = sp2, III = sp3
I = sp3, II = sp2, III = sp
I = sp, II = sp2, III = sp
I = sp2, II = sp3, III = sp2
I = sp2, II = sp, III = sp2
HH H C H H C H C H H H
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