Question

Tests reveal that a normal driver takes about 0.75 s before he or she can react to a situation to avoid a collision. It takes about 3 s for a driver having 0.1% alcohol in his system to do the same.(Figure 1). Figure < 1 of 1 > - 44 ft/s - Pai

Answer 1

Answer:

tests reveal that a normal driver takes about 0.75 s before he or she can react to a situation to avoid a collision. It takes about 3 s for a driver having 0.1 % alcohol in his or her system to do the same.

O Given that "10 avoid a collision, normal driver takes t 0.75 $ to read *10 avoid a collision, drunken reart driver takes t = 35 to Speed of the cars in both the cases is vo= 44 ft/s Deceleration of the cars in both the cases is ac = 20ft/s² Distance travelled by the normal driver before he can react is expressed as d'avot de 44x0.75 ď = 33ft velocity as a function of position is expressed as bol = 0g At a acls-so) Here, . So = 33ft sad

Accordingly we have 10=(44) 2+26-20) (d-33) 0 : 1936 +2420) (d– 33) 0 =1936 - 40 (d-33) 8-1936 - Hod + 1320 0 = 3256-400 40d = 3256 - 3256 LLO d = 81.4 81 Shortest Stopping do'stance for the new mal driver is d = 8) #7 Distance travelled by the drunken driver before he can react is expressed as d' = vot d' - 4483 d = 13aft

velocity as a funetion of polition is expressed as v2 = y2 + aac (s-so) tere, So = 182 ft VOO Accordingly, we have 03(44)+al-20) (d.–132) C0 = 1936 - 40 (d-132) 0 2 1936 - 400+ 5280 0 1216-40d 40 d = 1216 d = 7216 40 " dz 180.4 180. Shos test stopping distance for the drunken driver is d=180 ft