A beam of laser light with a wavelength of ?=475.00 nm passes through a circular aperture of diameter ?=0.113 mm . What is the angular width of the central diffraction maximum formed on a screen? ?=
Sin theta = 1.22 × lamda÷ D
Or theta = sin^(-1) (1.22×4.75×10^(-7)÷1.13×10^(-4))
Or theta = 0.2938°
Now angular width = 2×theta = 0.5876°
A beam of laser light with a wavelength of ?=475.00 nm passes through a circular aperture...
A beam of laser light with a wavelength of 1 = 560.00 nm passes through a circular aperture of diameter a = 0.189 mm. What is the angular width of the central diffraction maximum formed on a screen? A=
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