SolutionA:
unbiased estimated of m=sample mean
=m=sample mean=81.1+84.7+77.8+76.4/4=320/4=80
m=80
SolutionB:
unbiased estimated of sigma^2=sample variance
given m=79
X | XBAR | X-XBAR | (X-XBAR)^2 |
81.1 | 79 | 2.1 | 4.41 |
84.7 | 79 | 5.7 | 32.49 |
77.8 | 79 | -1.2 | 1.44 |
76.4 | 79 | -2.6 | 6.76 |
TOTAL | 45.1 |
s^2=45.1/4-1=45.1/3=15.033
ANSWER:
s=15.0333
unbiased estimator for sigma^2 when m is known=15.0333
Solutionc:
here m is not given
so sample mean=m=80
X | XBAR | X-XBAR | (X-XBAR)^2 |
81.1 | 80 | 1.1 | 1.21 |
84.7 | 80 | 4.7 | 22.09 |
77.8 | 80 | -2.2 | 4.84 |
76.4 | 80 | -3.6 | 12.96 |
TOTAL | 41.1 |
s^2=45.1/4-1=41.1/3=13.7
ANSWER:
unbiased estimator for sigma^2 when m is not known=13.7
Show steps thanks 1. The numbers 811, 84.7, 77.8, 76.4 represent the temperature measured at a...
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