Question

"Multiple Function Returns Using Memory Pointers"

Contents of employee.dat... copy paste and create a file (employee.dat)

123-45-6789 Kirk James 44.7 88.99 0.0175
124-89-0007 Bond Jane 45.6 65.75 0.04
405-77-8911 Puff Blossom 40 33.88 0.03
405-10-9871 Puff Buttercup 41.2 45.66 0.047
223-03-8761 Puff Bubbles 37.8 33.44 0.015
980-11-2201 Joneski Kasey 23.1 10.77 0.033
115-88-7619 Crooke I.M.A. 25.4 88.75 0.02
777-00-1232 Smith Alias 43.5 22.3 0.034
345-89-0022 DeMann Stan 56.7 29.45 0.065
210-37-1192 Jones Jeane 48.9 20.33 0.025
103-22-4321 Smith Alias 33.5 19.67 0.063

C++

The problem with using functions is that C++, by default will return not more than one value to the calling routine (i.e. main( ) for example). Using pointers, we can “return” more than one value to that calling routine. This allows us to “farm” out intermediate calculations to functions for later use in the logic and then pass those values on to other functions as needed.

In this exercise, we will read in a data file of employees (file is furnished to you, “employee.dat”):

1. Employee SSN

2. Employee Last Name

3. Employee First Name

4. Hours Worked

5. Pay Per Hour

6. Personal Income Tax Rate

Your assignment’s logic is to:

1. Read in the records from the file,

2. Pass the Hours Worked, Pay Per Hour, Personal Income Tax Rate to a single function to determine:

3. Whether or not overtime pay is computed (anything over 40 hours is overtime at 1.5 times the regular pay). Compute any overtime pay at 1.5 times pay rate

4. Compute the regular pay at regular hours (40 hours or less)

5. Compute the gross pay (Regular Pay plus any overtime pay)

6. Compute the personal income taxes withheld

7. Compute Net Pay (gross pay minus personal income taxes withheld)

8. Pass ALL these values BACK to the main calling routine from this one function.

9. Display:the Employee SSN, Last Name, First Name, Total Hours, Regular Hours, Overtime Hours (if any), Pay Per Hour, Personal Income Tax Rate, Regular Pay, Overtime Pay (if any), Gross Pay, Withheld Income Taxes, Net Pay.

Answer 1

Note: Could you plz go through this code and let me know if u need any changes in this.Thank You
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#include <iostream>
#include <string>
#include <cmath>
#include <fstream>
using namespace std;
void readFile(string ids[], string fnames[], string lnames[], double hoursWork[], double payRate[],double taxrate[], int cnt);
void calculateGrossNetPay(double* hoursWork, double* payRate, double* normalPay, double* overtimePay,double* grosspay, double* taxRate,double* taxWithHeld,double* netPay,int cnt);

void displayReport(string* ids, string* fnames,string* lnames, double* hoursWork, double* payRate, double* grossPay,double* normalPay,double* overtimePay,double* taxRate,double* taxWithHeld,double* netpay, int cnt);
int main()
{
int choice;
int cnt = 0;
string* ids;
string* fnames;
string* lnames;
  
double* hoursWork;
double* payRate;
double* taxRate;
double* normalPay;
double* overtimePay;
double* taxWithHeld;
double* grossPay;
  
double* netpay;
//defines an input stream for the data file
ifstream dataIn;

string id;
           double hw;
string fname,lname;
double pay,taxR;
dataIn.open("employee.dat");
//checking whether the file name is valid or not
if (dataIn.fail()) {
cout << "** File Not Found **";
exit(0);
}
else {
while (dataIn >> id >> fname >>lname>> hw >> pay>>taxR) {
cnt++;
}
dataIn.close();

// Creating array dynamically
ids = new string[cnt];
fnames = new string[cnt];
lnames = new string[cnt];
hoursWork = new double[cnt];
normalPay = new double[cnt];
overtimePay = new double[cnt];
grossPay=new double[cnt];
payRate = new double[cnt];
taxRate = new double[cnt];
taxWithHeld=new double[cnt];
readFile(ids,fnames,lnames,hoursWork,payRate,taxRate,cnt);

calculateGrossNetPay(hoursWork, payRate,normalPay,overtimePay,grossPay, taxRate,taxWithHeld,netpay, cnt);

displayReport(ids, fnames,lnames, hoursWork, payRate, grossPay,normalPay,overtimePay,taxRate,taxWithHeld, netpay, cnt);
  
}
return 0;
}
void readFile(string ids[], string fnames[], string lnames[],double hoursWork[], double payRate[],double taxrate[], int cnt)
{
//defines an input stream for the data file
ifstream dataIn;
string id;
   double hw;
string fname,lname;
double pay,tax;
dataIn.open("employee.dat");
  
for (int i = 0; i < cnt; i++) {
dataIn >> id >> fname >>lname>> hw >> pay>>tax;
ids[i] = id;

fnames[i] = fname;
  
lnames[i] = lname;
  
hoursWork[i] = hw;

payRate[i] = pay;
  
taxrate[i]=tax;
  
}
dataIn.close();
  
}
void calculateGrossNetPay(double* hoursWork, double* payRate, double* normalPay, double* overtimePay,double* grosspay, double* taxRate,double* taxWithHeld,double* netPay,int cnt)
{
for (int i = 0; i < cnt; i++) {
if(hoursWork[i]<=40)
{
    normalPay[i]=hoursWork[i]*payRate[i];
   }
   else if(hoursWork[i]>40)
   {
      normalPay[i]=40*payRate[i];
      overtimePay[i]=(hoursWork[i]-40)*1.5*payRate[i];
   }
   grosspay[i]=normalPay[i]+overtimePay[i];
   taxWithHeld[i]=taxRate[i]*grosspay[i];
   netPay[i]=grosspay[i]-taxWithHeld[i];
}

}
void displayReport(string* ids, string* fnames,string* lnames,double* hoursWork, double* payRate, double* grossPay,double* normalPay,double* overtimePay,double* taxRate,double* taxWithHeld,double* netpay, int cnt)
{

  
for (int i = 0; i < cnt; i++) {
cout << ids[i] << "\t" << fnames[i]<<"\t"<<lnames[i] << "\t";
if(hoursWork[i]<=40)
{
   cout<<hoursWork[i]<<"\t";
       }
       else
       {
           cout<<"40\t"<<hoursWork[i]-40<<"\t";
       }
      
       cout<< payRate[i] <<"\t"<<normalPay[i]<<"\t"<<overtimePay[i]<< "\t" << grossPay[i] <<"\t"<<payRate[i]<<"\t"<<taxWithHeld[i]<< "\t" << netpay[i] << endl;
}
  
}

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Output:

CProgram Files (x86)\Dev-Cpp MinGW641bin\ReadFilelDFirstNameLastNameHoursWorkedPayRateTaxRate.exe 23-45-6789 124-89-000? 05-77-8911 05-10-9871 223-03-8761 980-11-2201 115-88-7619 77-00-1232 45-89-0022 210-37-1192 103-22-4321 Kirk Bond Puff Puff Put^ski 1.*sA0 Joneski Kasey 23.1 Cro Smith Alias40 DeMann Stan JoneSdeane4 Smith Alias33.5 4.7 5.6 33.88 1355.2 0 40 33.44 1264.03 10.77248.787 88.75 2254.25 0 3.5 16.7 8.9 19.67658.945 88.99 3559.6 627.38 4186.98 88.99 3.2721 4113.71 65.75 2630 40 552.3 3182.3 65.75 127.292 3055.01 1355.2 33.8840.656 1314.54 dane Blossom 40 Buttercup Bubbles 37.8 1.2 45.66 1826.4 82.188 1908.59 45.6689.7036 1818.88 1264.03 33.44 18.9605 1245.07 248.787 10.77 8.20997 240.577 2254.25 88.75 45.085 2209.16 117.075 1009.08 22.3 737.723 1915.72 29.45 124.522 1791.2 oke I.M.A. 25.4 22.3 29.45 1178 20.33 813.2271.405 1084.61 20.33 27.1151 1057?.49 892 34.3086 974.766 658.945 19.6741.5135 617.431 rocess exited after .1066 seconds with return value ress any key to continue -. .

__________________Thank You