Question

urgent

HULL I wil LJUR cuon 18/to the field. Write the correct answers in the space below Y e V Direction: 00 [4] #11. -806 uC of charge is uniformly distributed age is contained in a spherical region of radius 60cm concentric with the center o Le is uniformly distributed throughout a spherical volume whose diameter is 25.2 cm. How much of this Answers: 2-1.55 x 10- C. C. b.-2.21 x 10°C. radius 7.60 сm concentric with the center of the charge distribution? b.-2.21 x 10c. c.-3.55 x 10°C. C.-3.55 d. 4.55 x 10°C. e. -5.55 x 10°C. Point charges Q1 and O2 are located at two vertices of an equilateral triangle. Point P is the third vertex. e length of each side of the triangle is 35.8 cm. 0,- -200e and Q2 +330e. The electric potential at point P 15 (Assume that the potential is zero at infinity) Answers: a. +486 nV. b. +523 nV. C. -627 nv. d. +726nV. C.-828 V. f. [10] #13 Circle each of the TRUE statements below. a. The electric flux through a Gaussian surface is equal to the electric charge outside of the surface divided by 8.85 x 10-12 Coulomb/(Newton. m) b. Electric flux depends on the electric field passing through an area and the angle that the field makes with the surface of the area. c. Gauss's law is especially useful if there is a lot of symmetry in a problem. d. Gauss's law relates electric field and electric potential. e. A Gaussian surface is a closed imaginary surface

Answer 1

Angol2 9, =-200e Og = + 330 e 35. 8cm 35.8cm @= 1.681019 UUUUUU Q, 35.8cm Q2 electric potential at P due to 8 V = K9, - 9X10°x-200X1.5X1o9 3568x102 X V=-80.4469 X 100 OOOOO V = -804.5 X109 ✓ Polentina electric

-19 electric Polential due to a Vo = RP.2 - 9x18 x 330 X 16 X16 d 35.8x102 Va= 1327.374 x16v So Total electric Potential at P V=VTV2 V=(-804.5 +13.27.374) X10 = 5 23x10 W - 9 v = +523 mv option (6) is correct