Question

9] Suppose X is Normal random variable with mean 10 and SD 4. What is the probability that X is between 7 and 13? [10] Suppos
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Answer #1

9)

Given

\mu = 10, \sigma = 4

We convert this to standard normal as

P (X < x) = P( Z < x - \mu / \sigma)

So,

P( 7 < X < 13) = P (X < 13) - P( X < 7)

= P (Z < 13 - 10 / 4) - P (Z < 7 - 10 / 4)

= P(Z < 0.75) - P( Z < -0.75)

= 0.7734 - 0.2266

= 0.5468

10)

80th percentile = \mu + Z\sigma ,Where Z is critical value at 80% confidence level.

23 = \mu + 0.8416 * 4

Solve for \mu

\mu = 19.6336

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