Use the Method of Undetermined Coefficients to find the general solution for the differential equation: y"-2y'+2y= e^(x)sinx
Answer should be: y= ce^(x)cosx+ce^(x)sinx-(x/2)e^(x)cosx
.................(1)
for homogeneous system find roots
for complex roots complementary solution is
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here so assume that particular solution is in the form of
................(2)
take first derivative
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take second derivative
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put all value in equation 1
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compare coefficient both sides
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put both constant in equation 2
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general solution is
Use the Method of Undetermined Coefficients to find the general solution for the differential equation: y"-2y'+2y=...
8. Find the solution to the differential equation y"+2y'+y=sinx using the method of undetermined coefficients. 1 COS X (a) y=ce' +ce' + -cosx 2 (b) y = ce' +cxe'+ (c) y = cxe' +cze cos x (d) y= c,e* + c xe" COSX 1 (e) y=ce' + ce + sinx 2 (f) y=ce' + exe* + sin x 2 (g) y=cxe' + e*- sinx 2 (h) y=ce' + cxe' 1 sinx 9. Use the method of undetermined coefficients to find...
Find the general solution of the following differential equation by using the method of undetermined coefficients for obtaining the particular solution. y''-y'-2y=2sin(x) - 3e^(-x)
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