Question

er19 - BEYERSDORF> Activities and Due Dates > HW5 Resources Complete combustion of 6.80 g of a hydrocarbon produced 20.8 g of CO2 and 9.95 g of H20. What is the empirical formula for the hydrocarbon? Insert subscripts as necessary. empirical formula: CH

Answer 1

Given Compound Containing ard H Let the Compound formula be Hy Combuslion of the Campound gtiven, mass of C02 20.84 i herfore, mass of C. 20-8 χ r2 z 5.67 gm mol, mass f 20 9.95g Therefore. mass of H-9.95 x 2x 05 qm I8 Caledating mols of C and H: Moles of C570-4725 12 Moles of H L-05 . iidbq viith moles ( lbwer wier ) Mles of C. 0.4725-1 Moles-ofH-1-10 0-4725 43 0.4725

Multiply by gt whole number., 2 to gel whole, Moles of C 2XI2 Moles of H Thus, empirical formula C2H

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