Question

Assuming that the probability of a pea having a green pod is .018. When12 peas are generated, use binomial probability formula to find the probability of getting at least 2 green peas.

Answer 1

We have here given, n=12 , p= 0.018

$X\sim Binomial(n=12,p=0.018)$

The probability of getting at least 2 green peas

$P[X\geq 2]$

$=1-P[X<2]$

$=1-P[X\leq 1]$

=1-{P[X=0]+P[X=1]}

$=1-\left \{ C(12,0) *(0.018)^{0}*(1-0.018)^{12}&plus;C(12,1) *(0.018)^{1}*(1-0.018)^{11}\right \}$

=1-{0.8042+0.1769}

=0.0189