Determine the concentration of a solution prepared by diluting 25.0 mL of a stock 0.188 M...

Question

Question

Answer 1

✔ Recommended Answer

Answer #1

We can use the following formula

Va X Na = Vb X Nb

Va = 25 ml Na = 0.188 M Vb = 150 ml

Let us substitute the valeus and calculate the final concentration.

Nb = 25 x 0.188 / 150 = 0.0313 M

Hence the final concentration is 0.0313 M.

Option B is correct answer

Answer 2

Similar Homework Help Questions

What is the concentration of a KOH solution prepared by diluting 25.0 mL of a 6.0...

What is the concentration of a KOH solution prepared by diluting 25.0 mL of a 6.0 M stock solution to a dinal volume of 1.00 L?
What is the concentration of a solution prepared by diluting 25.0 mL of a 4.50 M...

What is the concentration of a solution prepared by diluting 25.0 mL of a 4.50 M H2SO4 solution to a final volume of 1.00 L?
Determine the concentration of a solution prepared by diluting 20.0 mL of a 0.200 M LiOH...

Determine the concentration of a solution prepared by diluting 20.0 mL of a 0.200 M LiOH to 250.0 mL.

Determine the concentration of a solution prepared by diluting 20.0 mL of 2.00 M NaCl to...

Determine the concentration of a solution prepared by diluting 20.0 mL of 2.00 M NaCl to 250.0 mL
What is the concentration of a solution formed by diluting 25.0 mL of a 3.2 M...

What is the concentration of a solution formed by diluting 25.0 mL of a 3.2 M Naci solution with 59 mL of water? O 27 M NaCI O 0.50 M NaCl O 10 M NaCI O 0.59 M NaCl O 1.18 M NaCl
A solution of HCl is prepared by diluting 25.0 mL of a 1.0 M HCl solution...

A solution of HCl is prepared by diluting 25.0 mL of a 1.0 M HCl solution with enough water to make 750 mL of HCl solution. (Show your work for all calculations!) a) What is the molarity of the HCl solution? b) What is the [H3O+] and the pH of the HCl solution? c) Write the balanced chemical equation for the reaction of HCl and Ba(OH)2 d) How many milliliters of the diluted HCl solution is required to completely react...

You have prepared a solution by diluting 10.00 mL of 1.213 M Cu(NO3)2 to a total...

You have prepared a solution by diluting 10.00 mL of 1.213 M Cu(NO3)2 to a total volume of 50.00 mL. What is the concentration of Cu2+ ions in the resulting solution? Report your answer to 3 decimal places.
You have prepared a solution by diluting 17.00 mL of 1.258 M Cu(NO3)2 to a total...

You have prepared a solution by diluting 17.00 mL of 1.258 M Cu(NO3)2 to a total volume of 50.00 mL. What is the concentration of Cu2+ ions in the resulting solution? Report your answer to 3 decimal places.
4. What is the molar concentration of a solution that results from diluting 25.0 mL of...

4. What is the molar concentration of a solution that results from diluting 25.0 mL of a 0.45 M solution of KOH 500.0 mL? a) 44 M b) 11 M c) 9.0 M d) 0.11M e) 0.022 M

1. A series of dilute NaCl solutions are prepared starting with an initial stock solution of...

1. A series of dilute NaCl solutions are prepared starting with an initial stock solution of 0.100 M NaCl. Solution A is prepared by pipeting 10 mL of the stock solution into a 250-mL volumetric flask and diluting to volume. Solution B is prepared by pipeting 25 mL of solution A into a 100-mL volumetric flask and diluting to volume. Solution C is prepared by pipeting 20 mL of solution B into a 500-mL volumetric flask and diluting to volume....