Question

note** : Each underlined atom is the central atom of the molecule.

Instructions:

For each compound , draw the 3D structure for the underlined atoms, determine the hybridization and geometry of the underlined atom, determine the angles of the underlined atom and determine the orbitals of two different bonds AROUND the central atom. (underlined atom)

(CH3)3C (CH3)2N (CH3CH2)20-BF3 CICO2CH2CH3

Answer 1

(CH3),c* * é Hybridisation > Sp3 Geometry - Tetrahednal Angle z 109°281 CH3 (2) (CH3)2N CH3 N ₂CH3 (3) (CH₃ CH2), O- BF3 * Hybridisation = sp3 d. 3 Geometry Trigonal Bipy samadal Angle = 120°, 900 Hybridisation of o sp3d2 Hybridisation of Ba sp3 Geometry of CO² & Octanedral Geometry of B & Tetrahedral Angle of ' 900 Angle of 'B' 109°281 0-B-F CH₂CH3 (4) CICOLCH₂CH₂ ☆al-e-o-eH₂CH₂ Hybridisation of 'e'o sp2 Geometry = plamer trigonal Angle = 120°. From (1) to (3) all compounds have apo orbital around central atom. But in compound (4) it have one L' arbital and one '3p' orbital around it.