What is the pH at the equivalence point when 0.112 M hydroxyacetic acid is titrated with...

Question

Question

What is the pH at the equivalence point when 0.112 M hydroxyacetic acid is titrated with 0.0500 M KOH?

Answer 1

Answer #1

Date 10 Page Losuming Lofo 아 Concenhahona 3 24 L

Answer 2

Similar Homework Help Questions

When a weak acid is titrated with a strong base, if the pH at the half-equivalence...

When a weak acid is titrated with a strong base, if the pH at the half-equivalence point is 6.04, what is the Ka of the acid?
What is the pH at the equivalence point when 85.0 mL of a 0.175 M solution...

What is the pH at the equivalence point when 85.0 mL of a 0.175 M solution of acetic acid ( CH3COOH) is titrated with 0.100 M NaOH to its end point?
Find the pH at the equivalence point of HA being titrated by BOH, where HA is...

Find the pH at the equivalence point of HA being titrated by BOH, where HA is a weak acid with a ka=4.3*10-4 and BOH is a strong base you have Building on problem 1, if you have 0.1 M NaOH and find your equivalence point at 23.78 mL added, how many moles of HA were present? Find the equivalence point and the pH at equivalence of .234 moles of citric acid being titrated with 0.100 M KOH. Acetic acid is...

What is the pH at the equivalence point if 25.0 ml of 0.015 M benzoic acid...

What is the pH at the equivalence point if 25.0 ml of 0.015 M benzoic acid (HC7H5O2 , pKa=4.19) is titrated with 0.025 M NaOH?
An unknown concentration of phosphoric acid is titrated to its equivalence point with 0.2701 M KOH....

An unknown concentration of phosphoric acid is titrated to its equivalence point with 0.2701 M KOH. What is the concentration of the acid? H3PO4 (aq) + 3 KOH(aq) - K3PO4 (aq) + 3 H2O) Initial volume of KOH solution 1.03 mL Final volume of KOH solution 15.02 mL Original volume of H3PO4 solution 24.68 mL O 0.001260M 0.05104 M 0.1531 M 0.4593M
An unknown concentration of phosphoric acid is titrated to its equivalence point with 0.2701 M KOH....

An unknown concentration of phosphoric acid is titrated to its equivalence point with 0.2701 M KOH. What is the concentration of the acid? H3PO4 (aq) + 3 KOH(aq) – K3PO4 (aq) + 3 H200) Initial volume of KOH solution 1.03 mL Final volume of KOH solution 15.02 ml Original volume of H3PO, solution 24.68 ml O 0.001260M 0.4593 M 0.05104 M 0.1531M

2. Calculate the volume of potassium hydroxide at equivalence point and the pH at equivalence point...

2. Calculate the volume of potassium hydroxide at equivalence point and the pH at equivalence point when 10.00 16 of 1200 mM solution of acetic acid was titrated with 9.500 ml potass- sium hydoxide. pka value for acetic acid is 4.76. = 0.012 M acetic acid 12.00m M I M (millionlar) x 1000mm 9.500m IM * 1000 mm - 0.098M KOH mv = Mava of (0.012)(0.016) = 60.0095m) (V2) V2 = 0.012632 = 12.63 m2
A.) A 20.0 mL sample of 0.0600 M carbonic acid (H2CO3) is titrated with 5.00 mL of 0.0960 M KOH...

A.) A 20.0 mL sample of 0.0600 M carbonic acid (H2CO3) is titrated with 5.00 mL of 0.0960 M KOH. What is the solution pH to the nearest hundredths place? pKa1 = 6.35 and pKa2 = 10.33. B.) A 20.0 mL sample of 0.0600 M carbonic acid (H2CO3) is titrated with 0.0960 M KOH. How many mL of titrant are required to reach the first equivalence point? C. )A 20.0 mL sample of 0.0600 M carbonic acid (H2CO3) is titrated...
calculate the pH of the solution at the equivalence point when 25.0 mL of .10 M...

calculate the pH of the solution at the equivalence point when 25.0 mL of .10 M benzoic acid is titrated with 0.10 M potassium hydroxide. The Ka for benzoic acid is 6.3 x 10^-5

A 15 mL sample of hydrofluoric acid, Ka=6.8x10^-4 was titrated with .475 M KOH. The equivalence...

A 15 mL sample of hydrofluoric acid, Ka=6.8x10^-4 was titrated with .475 M KOH. The equivalence point was reached after addition of 19.35 mL of base. Determine the molar concentration of the original hydrofluoric acid solution, and find the pH of the solution.