Write a program in Java that will simulate FCFS (First Come First Serve) considering context switching is 0. The program should compute waiting time and turnaround time of every job as well as the average waiting time and average turnaround time. Then change the context switching time to 0.4 milliseconds.
Dear student,
as per property of FCFS, the process coming first will be executed completely without any interruption or context switching.
The java program is provided below. It simulate FCFS, which sorts processes according to their arrival time and executes and computes waiting & arrival time. It also calculates their average waiting and average arrival time.
import java.util.Scanner;
public class FCFS {
public static void main(String[] args) {
Scanner sc = new
Scanner(System.in);
int n, i, j, temp, time=0;
float avg_wt=0, avg_tt=0;
System.out.println("Enter no. of
processes");
n = sc.nextInt();
int at[] = new int[n+1]; // Arrival
time
int ft[] = new int[n+1]; // Finish
time
int tt[] = new int[n+1]; // Turn
around Time
int wt[] = new int[n+1]; // Waiting
time
int ct[] = new int[n+1]; //
CPU/Burst time
String p[] = new String[n+1]; //
Process name
String ts;
System.out.println("Insert details
of processes as (Arrival_time, CPU_time)");
for(i=1;i<=n;i++)
{
System.out.println("Process "+i);
at[i] =
sc.nextInt();
ct[i] =
sc.nextInt();
ft[i] = 0;
wt[i] = 0;
tt[i] = 0;
p[i] =
"p"+i;
}
// sorts processes according to
their arrival times
for(i=1;i<n;i++)
{
for(j=0;j<n;j++)
{
if(at[j]>at[j+1])
{
temp = at[j];
at[j] = at[j+1];
at[j+1] = temp;
temp = ct[j];
ct[j] = ct[j+1];
ct[j+1] =
temp;
ts = p[j];
p[j] = p[j+1];
p[j+1] = ts;
}
}
}
// Process each task
for(i=1;i<=n;i++)
{
if(at[i]<=time)
{
time += ct[i];
ft[i] += time;
tt[i] = ft[i]-at[i];
wt[i] = tt[i]-ct[i];
avg_tt += tt[i];
avg_wt += wt[i];
}
else
{
while(at[i]>time)
time++;
time += ct[i];
ft[i] = time;
tt[i] = ft[i]-at[i];
wt[i] = tt[i]-ct[i];
avg_tt += tt[i];
avg_wt += wt[i];
}
}
avg_tt /= n;
avg_wt /= n;
System.out.println("\nProcess AT
\tFT \tCT \tTT \tWT");
for(i=1;i<=n;i++)
{
System.out.println(p[i]+"\t"+at[i]+"\t"+ft[i]+"\t"+ct[i]+"\t"+tt[i]+"\t"+wt[i]);
}
System.out.println("\nAverage
turnaound time = "+avg_tt);
System.out.println("Average waiting
time = "+avg_wt);
sc.close();
}
}
The output of this code for example provided by you is given below.....
Enter no. of processes
6
Insert details of processes as (Arrival_time, CPU_time)
Process 1
0 6
Process 2
3 2
Process 3
5 1
Process 4
9 7
Process 5
10 4
Process 6
11 3
Process AT FT CT TT
WT
p1 0 6 6
6 0
p2 3 8 2
5 3
p3 5 9 1
4 3
p4 9 16 7
7 0
p5 10 20 4
10 6
p6 11 23 3
12 9
Average turnaound time = 7.3333335
Average waiting time = 3.5
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