Question

a=4.5 and b=0.2

(b) Convert the following to the specified (length Il mass Il time ) unit system, using the values of a and b from Question 0. Enter ONLY the values in the template, NOT the units. SI → Imperial (ft // slug // s) Imperial → SI (mm // tonnells) (0) 73a kN 5a MPа 99a x 10 mm 81a N mm (vii) 687a ft-lbf 8a lbs 65b ksi 65b Msi (iv) (vii)

Answer 1

Question: convert the following to the specified unit system using the values of a=4.5 and b=0.2?

U UUUUUUU The values given in the question are: a=4.5 and b =0.2 Conversion of units from 51s Imperial G) 73 a kN = 73X4.5 = 328.5 KN IKN = 104.82 slug 328.5 KN = 328.5 X104.82 - 34433-37 slug Hence, 730 KN = 344 33-37 slug (11) 50 MPa = 5X4.5 = 22.5 MPa = 22.5 N/mm? IMPa = 145-038 Psi 22.5 MPa = 22.5 X 145.038. = 3263.349 Psi Hence, 50 MPa = 3263.349 Ps; VVVV UUUUUUUUUUUUU (ii) 990 x 10" mm" :998 4.5 2109 - 445.5x109 mm" imm = 0.0393701 inch. (Umm" - (0.089 3701)" inch" immy = 0.0000024025 inch" LÀ 5. 5 x10 = 4 5. 5 X 107 x 0-00 00 0 2025 = 1070.32 x 103 inch Hence, 99 a xio mm" - 1070.32x10 inch

(iv) 812 N mm 81x4.5 = 364.5 NMM IN = 0.224809 pound fonce ie lbf imm = 0.0393701 inch 364.5 Nimm = 364.5 X0224809 X 0.0393701 = 3.226097 lbf.in Hence, 8ia Nimm - 3.226097 (bf.in. Conversion of units from Imperial - Si (v) 6870 ft-lbf - 687X4.5 = 3091.5 ft-lbf Ift = 0. 3048 m 11b = 4.44822N 3091-5 ft-lbf - 3091.5 X0.3048 x 4.44822 4191.511183 Nm Hence, 6870 ft-lbf = 4191.51183 N.M. M:) sa lbs = 8x4.5 = 361bs UUUUUUU Ilbs = 0.453592 kg 36 lbs = 36 20.453592 = 16.329323 kg Hence, 80lbs = 16.329323 kg

(Vis) 65 b ksi = 65 x0.2 = 13 KS: Iksi = 6.89476 MPa 13ksi = 13 X 6.89476 - 89.63188 MPa Mence, 65b ksi = 89.6318-8 MPa (Visi) 65 b Msi : 65 x 0.2 2 13 MST IMsi - 6894.76 MPa 13 MSi = 13 X 6894.76 89631.88 MPa Hence 65 b Msi = 89631.88 MPa