Find the arc length of the curve on the given interval. x = x2 +8, y...
Find the arc length of the curve below on the given interval. X 1 y= on (1,3] 4 2 8x The length of the curve is (Type an exact answer, using radicals as needed.)
Find the arc length of the curve below on the given interval. 1 y = + on [1,2] 4 8x The length of the curve is I (Type an exact answer, using radicals as needed.)
Find the arc length of the curve y - x over the interval 1,12 (a) 8 points Using the Fundamental Theorem, Part 2 (b) 2 points Use your "DEFINT" program to find M,1, T1 and Sz2 (c) 2 points Using your TI-84's built-in Integral calculator using MATH >>> MATH >>9: fnlnt (d) 2 points In your text book, there are formulas that give the maximum er in approximations given by MN, T, and Sy for the integral A a f(x)...
= In x 5. Find the arc length of the curve f(x) x2 between x = 8 perfect square, so the integrand simplifies nicely. 1 and x = 5. Note that 1+(f'(x))2 is a
(10pts) Find the arc length of the curve y = (x2 +1)3/2,0 5 x 51 using Formula L = S V1 + (f'(x))2 dx
what is the answer? (1 point) Finding the length of a curve. Arc length for y = f(x). Let f(x) be a smooth function over the interval [a, b]. The arc length of the portion of the graph of f(x) from the point (a, f(a)) to the point (b, f(b)) is given by V1 + [f'(x) dx Part 1. Let f(x) = 2 ln(x) - Setup the integral that will give the arc length of the graph of f(x) over...
Find the arc length of the graph by partitioning the x-axis. {(x2 + 133/2, from * = 3 to x = 6 y = 4. [-/3 Points] DETAILS SULLIVANCALC2 6.5.029. For the function, do the following. y = 16 – x2, from x = 0 to x = 1 (a) Use the arc length formula (1), dx, to set up the integral for arc length s. SV 3+ [fc] 1) ox S = (b) If you have access to a...
(2 points) Find the exact length of the curve y = In(sin(x)) for #/6 <</2. Arc Length Hint: You will need to use the fact that ſesc(x) dx = In|csc() - cot(3) + C.
Express the Arc Length of the given curve on the specified interval as a definite integral. Don't evaluate, just set it up. y=ez) on (0.2]
Find the arc length of the curves on the given interval 1 17. x = + for 1 Sys2 4 8y2