Question

B A flexible loop has a radius of 10.5 cm and it is in a magnetic field of B = 0.132 T. The loop is grasped at points A and B and stretched until its area is zero. It takes 0.162 s to close the loop. What is the magnetic flux B through the loop before it is streched? 4.70x10^-3 T'm^2 Hints: What is the area of the circle? What is the relationship between the magnetic flux Og and the flux-density B? What is the angle between the magnetic field vectors and the normal vector of the loop? What is the unit of the magnetic flux? Submit Answer Incorrect. Tries 1/20 Previous Tries What is the magnetic flux through the loop after it is stretched? Submit Answer Tries 0/20 What is the magnitude of the average induced electromotive force e in the loop during the stretching process? Submit Answer Tries 0/20

I NEED HELP WITH ALL THREE PARTS PLEASE

Answer 1

This is the question of electromagnetic induction.

I did my best to explain you,I use SI unit for answers.read lenz's law and Faraday's law for better understanding.

First page According to question we have flexible loop of radius 10.5c.m. We should calculate all the answers In SI unit So Area radius = 10.5cm = 0.105 meter of circle= TLX (radius)? A = 22xC0.10572 A = 0.03465 meter? 7 Here angle between the magnetic field Vectors and Normal vector of the loop is 180° Because in the given image magnetic field is denoted by the symbol "X" means the direction of magnetic field is normaly downwards to the plane of paper and Normal Vector of the lone is normaly upwards to the plane of paper.

Second page (1) Now loop the magnetic flux Ø before it is streched through the is given by OB = B. A. Cos 180 ile silt houba R = B. A = BACose da where o is the angle Between magnetic field i and area of loop = Here B= 0.132 Tesla (given ) So $8 = 0.132 0.03465 XC-1) ØB = -0.0045738 = -4.5 738 x169 webers Here negative sign indeeate that flux is entering through the loop. When the loop is stretched the Area of loop is zeso (2) T Sofa = B. A cose hall ØB = 0.132 X OX COS 180 ØB = 0 There is no any flux through the loop when It is streched.

third page (3) The magnitude of the average in Induced electromotive force & in the doop during the stretching process is given by The Faraday's Electromagnetic Induction Law Ad & = NdL a -N (02- 0 3 blot E = dt (t2-ti) Here N is number of turn in the loop t is the time - (Ø stretched - loop ) erod average E= -1 time taken E = -(0-(-4.5738 XL6?) 0.162 &= - 4-5738x103 ant 0.162 = -28.23x10 3 volt negative sign of induced B to A. Indeeate emf is that the clockwise direction from