TO Test :-
H0 :- σ12 = σ22
H1 :- σ12
σ22
Test Statistic :-
f = 68.4 / 15.7
f = 4.36
P value = 2 * P ( f > 4.3567 ) = 0.0038 ( From chi square table )
Reject null hypothesis if P value < α = 0.05
Since P value = 0.0038 < 0.05, hence we reject the null
hypothesis
Conclusion :- We Reject H0
Reject H0, there is sufficient evidence of a differene between σ12 and σ22.
Part b)
f(0.05 , 12 , 20 ) = 2.28
f > f(0.05 , 12 , 20 ) = 4.3567 > 2.2776 , hence we reject
the null hypothesis
Conclusion :- We Reject H0
Reject H0, There is sufficient evidence that σ21 and σ22.
The following information is available for two samples selected from independent normally distributed populations. Complete parts...
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