2. (5 points) Find the solution of the following Initial Value Problem dy +9=1, y(0) =...
-/1 POINTS Solve the initial value problem: dy + 2 y = 0 Y(0) = 5 x(t) = . Submit Answer Practice Another Version
Find the solution to the initial value problem: dy dy/dx=x^ 2√1 + x^3/1+cos y y(0)=2 the 1+x^3 is all in square root.
dy Find solution for initial valued problem:-3y + 2 3t ,y(0)--1 dt
dy Find solution for initial valued problem:-3y + 2 3t ,y(0)--1 dt
Find the solution ?y of the initial value problem
?″(?)=49(?′(?))10?5,?(1)=0,?′(1)=1.
?(?)=
(10 points) Find the solution y of the initial value problem 4 (v(1) 10 y (t) = y(1) = 0, y (1) = 1. y(t) = (1/^4)^(1/9) Σ Help Entering Answers Preview My Answers Submit Answers Show me another Results for this submission Entered Answer Preview Result [1/(t^4)]^(1/9) C) incorrect
(1 point) Find the solution to initial value problem ,dy – 14 + 49y = 0, y(0) = 2, y(0) = 3 dt g(t) =
2.8. Find the exact solution of the initial value problem (2.31). dY (2.31) (Y(0) =0 on the interval [0, 1] by Euler's method
3. (20 points) Find the solution y = y(x) of the initial value
problem y 0 − y x = cos2 (y/x) , y(1) = π 3
3. (20 points) Find the solution y = y(x) of the initial value problem 37 - = cos”(y/2),y(1) = 5
Solve the initial value problem. 9 dy 3 +5y 3 e 0, y(0)=7 dx The solution is y(x) =I
Solve the initial value problem. dy = x(y-5), y(0) = 7 dx The solution is (Type an implicit solution. Type an equation using x and y as the variables.)
Solve the initial value problem. 7 dy + 9y - 9 e-X = 0, y(0) = dx 8 The solution is y(x) =