Solution:
2,4-heptanedione, is an active methylene compound, has methylene (CH2) group flanked between two C=O groups, which makes it highly acidic. Therefore, pka of the compound is 9.
In 2,6-heptanedione, CH2 group is not flanked between two C=O groups, hence posses less acidity and thus, pka of the compound is higher upto 20.
CH3COCH2COCH2CH2CH3 ( 2,4-heptanedione)
CH3COCH2CH2CH2COCH3 (2,6-heptanedione)
3) Explain why 2,4-heptanedione is more acidic (pKa 9) than 2,6-heptanedione (pKa 20)
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Explain why cyclopentadiene (pKa 16) is many orders of magnitude more acidic than cyclopentane (pKa > 50). (Hint: Draw the structural formula for the anion formed by removing one of the protons on the −CH2− group, and then apply the Hückel criteria for aromaticity.) Explain why cyclopentadiene (PK, 16) is many orders of magnitude more acidic than cyclopentane (pka > 50). (Hint: Draw the structural formula for the anion formed by removing one of the protons on the -CH2- group,...
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Provide a resonance structures which explain why ortho and para nitrophenol are much more acidic than phenol
Explain why compound A is more acidic using resonance structures and question 21. WILLUDUlyalli Clemsty ENAM 20. Explain why Compound A is more acidic than Compound B. Use resonance structures to e 21. Which of the following is the least stable carbocation? Circle your response. (2) IV