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What is the concentration of Cut2 in a solution if a 25.00 mL aliquot, reacted with...
Determine the concentration of Acetic acid in the 25.00 mL aliquot. a) 18.05 mL of 0.1282...
Determine the concentration of Acetic acid in the 25.00 mL aliquot. a) 18.05 mL of 0.1282 M NaOh was used to titrate this solution. b) determine the concentration of acetic acid in your brand of vinegar (heinz) c)determine the mass of acetic acid present in 10.00 mL of JUST vinegar.
A titration was performed to standardize an EDTA solution. a) A 25.00 mL aliquot of a...
A titration was performed to standardize an EDTA solution. a) A 25.00 mL aliquot of a standard solution containing 0.01500 M Ca2+ required 42.87 mL of EDTA to reach the endpoint. The molarity of the EDTA solution is: ________ M b) That same EDTA solution was then used to titrate an unknown hard water sample. A 40.00 mL aliquot of unknown hard water required 34.21 mL of EDTA solution to reach a distinct endpoint. The concentration of Ca2+ ions (assuming...
1. What is the concentration of a citric acid sample if a 25.00 mL aliquot requires...
1. What is the concentration of a citric acid sample if a 25.00 mL aliquot requires 18.4 mL of 0.200 M KOH titrant to reach the endpoint. 2. How much 0.200 M KOH titrant will be required to reach the endpoint of a titration of 10.00 mL of 0.361 M citric acid?
If it requires 24.83 mL of a 0.205 M NaOH solution to titrate a 25.00 mL....
If it requires 24.83 mL of a 0.205 M NaOH solution to titrate a 25.00 mL. HCl solution, what is the concentration of HCI? Type your answer...
A 24.34 mL aliquot of a Pb2 solution, containing excess Pb2+, was added to 11.50 mL...
A 24.34 mL aliquot of a Pb2 solution, containing excess Pb2+, was added to 11.50 mL of a 2,3-dimercapto-1-propanol (BAL) solution of unknown concentration, forming the 1:1 Pb2+-BAL complex. The excess Pb2+ was titrated with 0.0157 M EDTA, requiring 9.88 mL to reach the equivalence point. Separately, 39.89 mL of the EDTA solution was required to titrate 32.75 mL of the Pb2+ solution. Calculate the BAL concentration, in molarity, of the original 11.50 mL solution concentration:
A 25.0 mL aliquot of 0.0440 M EDTA was added to a 49.0 mL solution containing...
A 25.0 mL aliquot of 0.0440 M EDTA was added to a 49.0 mL solution containing an unknown concentration of V3+. All of the V3+ present in the solution formed a complex with EDTA, leaving an excess of EDTA in solution. This solution was back-titrated with a 0.0340 M Ga3+ solution until all of the EDTA reacted, requiring 11.0 mL of the Ga3+ solution. What was the original concentration of the V3+ solution?
3. What is the molarity of an HCl solution when a 25.00 ml aliquot of 0.50M...
3. What is the molarity of an HCl solution when a 25.00 ml aliquot of 0.50M HCl is diluted to a volume of 500.0ml?
A 25.0 mL aliquot of 0.05600.0560 M EDTAEDTA was added to a 40.040.0 mL solution containing...
A 25.0 mL aliquot of 0.05600.0560 M EDTAEDTA was added to a 40.040.0 mL solution containing an unknown concentration of V3+V3+. All of the V3+V3+ present in the solution formed a complex with EDTAEDTA, leaving an excess of EDTAEDTA in solution. This solution was back-titrated with a 0.03300.0330 M Ga3+Ga3+ solution until all of the EDTAEDTA reacted, requiring 10.010.0 mL of the Ga3+Ga3+ solution. What was the original concentration of the V3+V3+ solution?
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of a 0.04152 M EDTA solution. The solution is then back titrated with 0.02204 M Zn2 solution at a pH of 5. A volume of 16.29 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and N solution is fed through an ion-exchange column that retains NP. The Cu2" that passed through the column...
A 1.000-mL aliquot of a solution containing Cu2 and Ni2 is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu2 and Ni2 is treated with 25.00 mL of a 0.04328 M EDTA solution. The solution is then back titrated with 0.02246 M Zn2 solution at a pH of 5. A volume of 21.60 mL of the Zn2 solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and Ni2 solution is fed through an ion-exchange column that retains Ni2 . The Cu2 that passed through the...
If it requires 24.83 mL of a 0.205 M NaOH solution to titrate a 25.00 mL. HCl solution, what is the concentration of HCI? Type your answer...
A 24.34 mL aliquot of a Pb2 solution, containing excess Pb2+, was added to 11.50 mL of a 2,3-dimercapto-1-propanol (BAL) solution of unknown concentration, forming the 1:1 Pb2+-BAL complex. The excess Pb2+ was titrated with 0.0157 M EDTA, requiring 9.88 mL to reach the equivalence point. Separately, 39.89 mL of the EDTA solution was required to titrate 32.75 mL of the Pb2+ solution. Calculate the BAL concentration, in molarity, of the original 11.50 mL solution concentration:
3. What is the molarity of an HCl solution when a 25.00 ml aliquot of 0.50M HCl is diluted to a volume of 500.0ml?
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of a 0.04152 M EDTA solution. The solution is then back titrated with 0.02204 M Zn2 solution at a pH of 5. A volume of 16.29 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and N solution is fed through an ion-exchange column that retains NP. The Cu2" that passed through the column...
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