Question

matlab

3) [3 pts) A circuit has a resistance of 52 in series with impedance across an inductor of 3 12. R=522 X: = 32 a) Find the magnitude of the total impedance b) Find the angle of the total impedance c) Find the source voltage if the current flows through the circuit is 2A.

Answer 1

Code:

R=5;
X=3;
total_impedance=power((R*R+X*X),0.5);
disp(total_impedance);

angle_in_degrees=atand(X/R);
angle_in_radians=atan(X/R);
disp(angle_in_degrees);
disp(angle_in_radians);

current=2;
voltage=current*total_impedance;
disp(voltage);

Image of the Code:

R=5; X=3; total_impedance=power ((R*R+X*X), 0.5); disp (total_impedance); Calculating total impedance EcoJouw NE Calculating angle of impedance in degrees Calculating angle of impedance in radians angle_in_degreesratand (X/R); angle_in_radians=atan (X/R); disp (angle_in_degrees); disp (angle_in_radians); current=2; voltage=current total impedance; disp (voltage) :| Calculating voltage

Image of the Output:

>> new 5.8310 30.9638 0.5404 11.6619

Explanation:

• We calculated the impedance by squaring both the R and X and adding them and taking square root of it.
• We calculated angle by dividing X and R and taking tan^-1 of the result.
• We calculated the voltage by multiplying current and total impedance ,i.e., Ohm's Law.

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