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Chapter 29, Problem 020 In the figure, part of a long insulated wire carrying current i = 2.10 mA is bent into a circular sec

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Answer #1

The system can be taken as two independent shapes of one coil and one straight wire.

The magnetic field due to the current is in the -z direction. (Right hand thumb rule)

Β = μοΙ /2πι-

When the coli is in plane with the wire, the magnetic field due to the coil will be in the +z directiin and is given by

Β = μο1/2r

So, the total magnetic field is

Here, I = 2.1 mA

r = 5.97 cm = 0.0597 m

Due to wire = 4*3.14*10^-7*2.1*10^-3/(2*3.14*0.0597) = 7.04 nT (nano tesla)

Due to coil = 4*3.14*10^-7*2.1*10^-3/(2*0.0597) = 0.221 nT.

So, total magnetic field = 0.221-7.04 = -6.819 nT

The first 3 answers are

1) 0 T

2) 0 T

3) -6.819*10^-9 T

When the coli is rotated 90 degrees,

The field due to the coil is in the +x direction.

So, answer for 4 is

4) 0.221*10^-9 T

5) 0 T (remains unchanged)

The field due to the wire remains in the - z direction.

6) -7.04*10^-9 T

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