Question

40Ω 48 Ω 0.5 A 80 2 32 S2 a) 50 2 75 2 4i 5 A +10 V 50Ω 25 Ω or the circuits shown above, select one of the problems to solve for the quantity indicated in the lection below. Only one problem will be evaluated, make sure your selection is accompanied with the quired value, as indicate below. he math procedure has an evaluation points of 40% of the total value. Note: Your selection should be either (a), (b) or (c)] 25pts a) Node-Voltage analysis to obtain the voltage at the current source. b) Mesh-current analysis to obtain 1, and I2 c) Any known procedure to obtain the current la.

Answer 1

Let, voltage across current source be 'V' volts rightarrow 48 & 32 Ohm Resistors are in series so, 48 + 32 = 80 Ohm rightarrow 30 Ohm & 30 are in parallel so, 80 Vertical-bar Vertical-bar 80 = 40 Ohm rightarrow Redrawn circuit By applying nodal analysis as follows rightarrow V - 12 /40 + 0.5 + V/40 = 0 2V - 12 + (0.5) 40 = 0 2V = 12 - 20 V = -8V Therefore voltage across current source is -8V because current through a series branch is same. so, In 'I_1' mesh only '5A' current source. And also current source direction 'I_1' direction is in the same so, I_1 = 5A By applying mech analysis to 'I_2' loop, rightarrow 25 I_2 + 75 I_2 + 10 V = 0 100 I_2 + 10 V = 0 I_2 = -10/100 = -0.1A Therefore I_2 = -0. 1 A \r\n let voltage 'V' at current source. rightarrow Nodal voltage analysis at 10 V source, 10 - V /2 + 10 - 12 /4 = 0