So, we have been given a = b (mod m) and we are asked to prove ac = bc (mod mc).
Or, we can also prove that ac - bc = 0 (mod mc).
Let's get to this.
Given, a = b (mod m)
We can write this as a - b = 0 (mod m).
Or, (a - b) = km ........................... (1)
Now, let's consider the left hand side of the equation we have to prove.
ac - bc = (a - b)c
We can substitute the value of (a - b) from equation (1).
We get ac - bc = kmc.
This means that (ac - bc) is divisible by mc.
So, ac - bc = 0 (mod mc)
Or, ac = bc (mod mc)
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