Find f(t). ℒ^−1 (4s / (s − 6)^2)
Use Theorem 7.1.1 to find ℒ{f(t)}. (Write your answer as a function of s.)f(t) = t2 + 4t − 2ℒ{f(t)} =
Use Theorem 7.1.1 to find ℒ{f(t)}. (Write your answer as a function of s.)f(t) = 10t − 8ℒ{f(t)} =
Use Theorem 7.4.1. THEOREM 7.4.1 Derivatives of Transforms If F(s) = ℒ{f(t)} and n = 1, 2, 3, . . ., then ℒ{tnf(t)} = (−1)n dn dsn F(s). Evaluate the given Laplace transform. (Write your answer as a function of s.) ℒ{3t2 cos(t)}
Use Theorem 7.4.1. THEOREM 7.4.1 Derivatives of Transforms If F(s) = ℒ{f(t)} and n = 1, 2, 3, . . . , thenℒ{tnf(t)} = (−1)n dn dsn F(s). Evaluate the given Laplace transform. (Write your answer as a function of s.) ℒ{t cos(7t)}
Use Definition 7.1.1.DEFINITION 7.1.1 Laplace TransformLet f be a function defined for t ≥ 0. Then the integralℒ{f(t)} = ∞e−stf(t) dt0is said to be the Laplace transform of f, provided that the integral converges.Find ℒ{f(t)}. (Write your answer as a function of s.)f(t) = et + 2ℒ{f(t)} = (s > 1)
Use Definition 7.1.1,DEFINITION 7.1.1 Laplace TransformLet f be a function defined for t ≥ 0. Then the integralℒ{f(t)} = ∞e−stf(t) dt0is said to be the Laplace transform of f, provided that the integral converges.to find ℒ{f(t)}. (Write your answer as a function of s.)f(t) = cos(t),0 ≤ t 0)
Use Definition 7.1.1.DEFINITION 7.1.1 Laplace TransformLet f be a function defined for t ≥ 0. Then the integralℒ{f(t)} = ∞e−stf(t) dt0is said to be the Laplace transform of f, provided that the integral converges.Find ℒ{f(t)}. (Write your answer as a function of s.)f(t) = 9, 0 ≤ t
Q2d 400 Gen(s+4)(s2+4s+5)(s+4s+2-3s+2+3) Find the partial fraction expansion of F(s) and then use the Laplace transform tables to find f(t) ft)- cos( t+ oju(t) COS
10s2s24 (1 point) Consider the function F(s) s3 4s a. Find the partial fraction decomposition of F(s) 10s2 s24 s3 4s b. Find the inverse Laplace transform of F(s). f(t) L1 F(s)} help (formulas)
QUESTION 12 Apply Laplace Inverse to find f(t): s +7 F(s) = 5(52 + 4s +3) Choose the correct answer: L-'[F(s)] = f() 1) f(1) = 4t’e-31 - 3e-+ + 7t 2) f(t) = 5t? - 3e-4 3) f(0) =2-31 - 3e-- + 4) f() = 6e-6 - e-31 +} QUESTION 13 Solve the ODE: 2 2 + 3ź - 2z = te-2 z(0) = 0 & ż(0) = -2 Choose the correct answer: 1) z(t) = -0.768 0.5t -...