Question

cores 0% Resources om Hint Check An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only a rope and a bag of tools. First he tries to throw a rope to his fellow astronaut, but the rope is too short. In a last ditch cffort, the astronaut throws his bag of tools in the direction of his motion, away from the space station. The astronaut has a mass of m, 102 kg and the top of tools has a mass of me - 13.0 ke If the astronaut is moving away from the space station at 1.20 m/s initially, what is the minimum final speed of the bag of tools with respect to the space station that will keep the astronaut from drifting away forever?

Answer 1

space station (Mat Mb V space station Var To keep astronaut from drifting away. Vaf > 0 Now Ma= 102 kg Mo = 1.0 kg V - 1.2 ms! Conservation of Linear Momentum , (Mat Mb) v = Ma C-var) + Mb (Vbf) → Vaf = (MoVoc - (MatM)x) > 0 → Vbf > / Ma + Mb v. = 10.6154 ms] . Ma VL 10.6 Mb