2)
We need to use standard normal z table to estimate the probability
P(-1.35<z<2.3) = P(z<2.3) - P(z<-1.35)
P(z<2.3) = 0.9893
P(z<-1.35) = 0.0885
Required probability = 0.9893 - 0.0885 = 0.9008
B)
From z table, p(z>1.95) = 0.0256
2. Find each probability for the standard normal distribution: a) P(-1.35 : <2.3) b) P(|=| >...
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