Ans 8
Clausius-Clapeyron equation
ln (P1/P2) =( Hvap /R) (1/T2 - 1/T1)
Normal boiling point occurs at 1 atm (760 mmHg)
P1 = 760 mmHg
P2 = 55.1 mmHg
T1 =?
T2 = 35+273 = 308 K
Hvap = 32.1*1000 J/mol
Gas constant R = 8.314 J/mol·K
ln (760/55.1) =( 32.1*1000 /8.314) (1/308 - 1/T1)
2.624 = 3860.957 (0.0032467 - 1/T1)
0.000679624 = (0.0032467 - 1/T1)
0.002567 = 1/T1
T1 = 389.54 K = 390K
Option D is the correct answer
8) Determine the normal boiling point of a substance whose vapor pressure is 55.1 mm Hg...
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