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monu olman A (+7c) 4cm B (+2.0c) 0 |2cm. .02m 11.24N/C C (-21c) 4. What is the net force (magnitude and direction) on the cha
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561 Given that адас B (+24) FBA 4cm - FBC 2cm (-2.4C) (6) FBA = KLAUB (4x10-2/2 = 9x 109 x 78 10-6x2x10-6 168104 FBA = 78.759x109 x 2x10-x (-2x 10-6 FBC - & KQB Qc (2x16-222 2x 2x 10-4 [Fec – – 90N ( } } (c) Net Force FB = FBA + FBC FB = 78.75. à nhope it helps...

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