The correct answer is option (i)
First we calculate sbar.
sbar=Average of all sample standard deviations
Sample standard deviation of sample 1=STDEV(B3:B5)=0.10
(Drag this cell formula to right to the rest of the samples till sample 10)
sbar=AVERAGE(B7:K7)=0.27
For n=3,from the control constants table,we have,B3=0 ;B4=2.568
UCLs=B4*sbar=0.69
LCL=B3*sbar=0
All the sample standard deviation values lie within the control limits.Hence,the process is in control.
Given the following measurements representing 10 samples of size 3. find the s-bar, UCL and LCL...
all in one I. Given the following table of coating weights for samples of size n-4: (a) Calculate the x 's and R's for samples 2 through & (b) Calculate the X and R values for all cight samples (c) Determine the appropriate constants that would be used with this data to constructx and R control charts, and calculate the control limits Range 18.5 17.9 19.6 22.2 16.5 19.0 2021.2 20.5 20.3 18.90 19.8 20.4 22.8 19.0 20.7 22.2 20.5...
I already have calculated for question #4 and got these numbers xdouble bar=28.07 UCL=29.08 LCL=27.08 ,Rbar=1.74, UCL=3.67, LCL=0 Sample Size=5 Continuing on from question #4, the employee continues to track the same data for 10 weeks after the supplier change, and gets the following data: Sample data: 1 2 3 4 5 6 7 8 9 10 Mean 27.8 28.9 27.4 28.7 28.0 27.1 27.2 27.3 28.0 27.4 Range 2.3 1.5 3.0 2.1 3.2 2.2 3.6 2.0 3.4 1.7 The...