Question

1315 atm 161 at 60.0 °C. What is the The vapor pressure of benzene is 100.0 mm boiling point of benzene at 760.0 mmHg? and 400.0 mm I 750 In Hvar ( ) 1:3768, ose 1.00 30016 - .0033416) . - AHUR (-3,4 x 10-4 ) 1,3868 8.3145 - 33.6)KT T - 4078-1235 12 100881425 8.8145 - 33411,3385 - A Hva 0 4099,667 Dlvy 33,91 11. Ethylene glycol CH OHCH,OH is a slightly viscous liquid and has boiling point of 198°C. Pentane, CH; has approximately the same molar mass as ethylene glycol. It is non viscous and has a boiling point of 36°C. Why is there such a significant difference in boiling points of the two substances? F i ne The edge length of the unit cell was found to be

Answer 1

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10. Pi = 100.0 mm Hg T = 26.100 = 299,1K P2= 400.0 mm Hg T2 = 60.0°C = 333K A Happe heat of vaporization - ? R = ideal gay equation - 0.008314 KT Ki molt Using clausius clapeyron equation In Bet = - DHwab G + in 400.0mm Hg 100e0 mm Hg = - Hvab 0.002314 KT KHmon) I 333K 299.12) & snap = 33.86 KI moln T DP 17 let the boiling point of benzene is P = 760.0 mm Hg In (P) --Hwab - in too. I'mm Hq ) = -33.86 kJ molt 7600 mm Hg / 0.0 → T 351.4K : 78.4°C 0.008314 KJ RYMON (299. IK I Hence, the boiling point of benzene is 78.400