Question

2. Design the 8” special shear wall shown below as a special using the simplified procedure. Pe = 20 k. vall shown below as a special masonry shear wall D=35 k L=20k (excluding selfweight) Vu= 55 k 10' 25° 20' 5' 5' 5 VIIMIIIIllIIlIlIl Re: Puw 1860) 10-15(20)40 515 (20) fm = 1,500 psi fv = 60 ksi -0.921) 30 (Hu-All P=A3 10175 P+0.575

Answer 1

TR gin diagran is a tantilaJer eson wall uito apenirgs. ID 35K, Lc2DK Rigi dity of ioll :e For eantila oll 3 Em 1 I.morrle of Inantia of wal S.SS t K Go Teiekn ot wall A = 8" 12 12 4eigpt ot lall : I5! 12 En 3X1 Pe 2-15 x10 in 5 5,oUD A U512)' 3x 3x108 x 2.15x10 momst Dalnetion. Evs0.4 En है) Now, 4 Seaar Deiuction EJ- A [l.2X550U 15x2 AArua of wal LO.4x3x10 q40 (15x12x8)nk uuo in Taguetig the operirgs 3, S0, total Dfleetion 41.67. Rigidity 2 1. FiOm prical formuls 40.11 (Bl)0.0233() 0-12x15/cato-0833(5 1 Ra (): u4.44 1 93.1 , rigid as solid wall प५.५५) ।० .So, ter wat ist ut. 6t