SOL)
Here,
x = 0.155 m
d = 0.235 m
A)
the gauge pressure of the oil interface , P = x * density of oil *g
P = 0.155 * 590 * 9.8
P = 896.21N/m^2 |
B)
the gauge pressure at the bottom of barrel , P b = P + d * density of water * g
P b = 896.21 + 0.235 * 1000 * 9.8
P b=896.21+2303
P b = 3199.21N/m^2 |
Question 1 Constants PartA A barrel contains a 0.155-m layer of oil floating on water that...