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(5 pts.) (b) Use a recursion tree to determine a good asymptotic upper bound on the recurrence T(n) = 6T ([n/4]) + 11n. Verif

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..hody at + T(n) = 6T(L1/4]) +110. The subproblem size fora node at depthi is oly. therefore, the free has egntl levels andverification by substitution method & we guess T(n) = cn (93 _dn T(n) = 6T(L2 + lin. 26. (c(014) 93 d (114)) + lin = (2293) C

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