Homework Answers
95% CI
| Given | |
| X bar | 65 |
| S | 28 |
| n | 49 |
α = 0.05
| CI | ||
| Zc | 1.959964 | +/- NORM.S.INV(α/2) |
| Upper | 72.83986 | X bar + Zc*(S/SQRT(n)) |
| Lower | 57.16014 | X bar - Zc*(S/SQRT(n)) |
We are 95% confident that population mean contained by this interval (57.16, 72.84)
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