Although an ideal voltmeter has an infinite internal resistance, this theoretical ideal is usually not met in practice. The voltmeter in the Figure has an internal resistance of 7 x 109 Ω and is used to measure the voltage across the resistor R2 as shown. Attaching this non-ideal voltmeter decreases the voltage across R2. Calculate the magnitude of this decrease using an emf of 16 V and R1 = R2 = 200 kΩ.
Although an ideal voltmeter has an infinite internal resistance, this theoretical ideal is usually not met...
Although an ideal voltmeter has an infinite internal resistance, this theoretical ideal is usually not met in practice. The voltmeter in the Figure has an internal resistance of 4 x 109 2 and is used to measure the voltage across the resistor R2 as shown. Attaching this non-ideal voltmeter decreases the voltage across R2. Calculate the magnitude of this decrease using an emf of 14 V and R1 = R2 = 250 ks2. Submit Answer This question expects a numeric...
RI Al huugh dn ideal vullme er has an 'nlinite in erna resis anue his lheur etical icledl is usually no me in practice The vollrreler in the Figure has an "ternal tesis an e o 6 x 10。Ω dnd is Attaching this non-ideal voltmeter decreascs the voltage across R2. Calculate the magnitude of this decrease using an emf of 20 used to measure the voltage across the resistor R as shown. Vand R1 = R2 = 150 kS2. R2...
A voltmeter has an internal resistance of 10 000 Ω and is used to measure the voltage across a 47.0-Ω resistor that, without the voltmeter connected, has a current of 1.20 A pass through it. How much current is drawn away from the circuit by the voltmeter when it is connected across the resistor? 4.7 mA 5.6 mA 1.205 A 0 A
8-1 12. A voltmeter with an internal resistance of 3.08 10.2 measures the voltage R, in the following figure across Ri in the following figure: R1 10.0 kΩ (3 marks) R2 20.0 kΩ 275 V a. What is the voltage across Ri in the absence of the meter? b. Draw the circuit diagram with the meter in place and calculate the effective resistance of the circuit. c. What is the voltage across R1 with the meter connected across it?
You have developed a new way to measure the internal resistance of a battery. The circuit you have created is shown below, with a non-ideal battery (EMF and internal resistance r in the red box), a constant external resistor R1-19.122, and a variable resistor R2. R2 has a resistance you can change over a wide range of values, from nearly zero to nearly infinity. In this circuit, you measure the voltage over R2, AV2. R1 is used to avoid damaging...
Internal resistance problem. Suppose that in Figure 3.3, Vo=13V, R1=150kΩ, R2=375kΩ, and Ri=2MΩ. Initially, the voltmeter is disconnected. If the internal resistance of the meter were 12 M Ω, what is the voltage across R2? Volts:
b) Suppose that the power supply is not ideal and to a good approximation can be modeled as an EMF of “E" with an internal resistance of "r". And suppose that r-2.0 Using the values of your theoretical treatment of your resistor network, solve for the value of ε¾ that existed while your resistor network was running. (5 pts) c) Suppose that the power supply is not ideal and to a good approximation can be modeled as an EMF of...
for circuit shown in figure the battery has no appreciable internal resistance. voltmeter and anmeter are ideal 2. (20 points, 5 points each) For the circuit shown in Figure, the battery has no appreciable internal resistance. Voltmeter and Ammeter are ideal. (a) What is the equivalent resistance of the circuit? 3 kn 2 kn R(series Rea» 3.734 3.21: 8-73 kn (b) What does the voltmeter read? parrele witn R4 . Vz4s τ24( 2 +): o.or7 (3.73 xu?): 47. 37lV (c)...
A battery provides a voltage of 8.00 V and has unknown internal resistance Rint. When the battery is connected across a resistor of resistance R1= 7.00 Ω , the current in the circuit is I1 = 1.00 A. If the external resistance is then changed to R2 = 5.00 Ω , what is the value of the current I2 in the circuit?
In the circuit shown the voltmeter (denoted by V) has an internal resistance of 90 Ω, the ammeter (denoted by A) has an internal resistance of 1 Ω. The battery with the emf of ℰ = 20V has a negligible resistance. Find the total dissipated power.