Question

Vcc = 15V R1 100k RC 800 C2 1E-5 Rsig C1 100 1E-5 R2 50k RE 400 Vin 4k Note: This circuit is the same common emitter circuit seen in HW18 and HW19 The internal capacitances are CBE = CBCT 10-12 F. You can assume that CCE is zero. a) Approximately, determine the poles associated with each internal capacitor. Use the Miller Theorem in your analysis of the poles associated with CBc. For CBE, use a test voltage to determine the equivalent resistance seen be CBE. b) Approximately, determine the high frequency 3dB cutoff

Assume DC bias current through the resister in parallel with the DC bias current source is negligible.

Answer 1