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Follow the instructions below for the remaining questions (on page 2) For Confidence Intervals you must state each of the fol
The American Veterinary Medical Association (AMVA) conducted a survey of veterinary clinics to estimate the proportion that d
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Solution:-

3) 95% confidence interval for the proportion of all vet clinics that do not treat large animals is C.I = ( 0.6988, 0.8234).

Point estimate = 137/180 = 0.7611

Margin or error = 0.0623

C.I pt2a/2x 1/P(1-p)

C.I = 0.76111 + 1.96 × 0.03178

C.I = 0.76111 + 0.06229

C.I = ( 0.6988, 0.8234)

95% confidence interval for the proportion of all vet clinics that do not treat large animals is C.I = ( 0.6988, 0.8234).

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