Question

very detailed work please

Determine the point on the x-axis through which passes the line of action of the standalone force that represents the force- couple system shown. (1) x- 2.09 ft (2) x = 1.6ft (3) x 0.625 ft (4) x 2.49 ft (5) x 2.33 ft (6) x-2.09 ft (7) x =-2.49 ft (8) None of the above R-500 Ib Mo- 800 lb-f

Answer 1

To form a couple of 800 lb by force of 500 lb the required distance r between parallel force as shown in figure should be r =800/ 500 =1.6

The x cordinate projection of this force is =1.6 sin40= 1.028

So ans is non of these

R 500 Ib M800 f