+10V 1 1/2 Vsa In teen D 4MA Given th (W) = 2m Alva 420) Via FIV. is in saturation (a) Assuminy Iva=orl Mi . input loop the KVL around O- Vs, + ID, --10=0. ► = Ķ In, - Vsi tlo. In: I (vsi to) ID; = 1.5 Vsi +15 - 0 =
and we have ID = 2 kn ( 4 / 4] (vas, vx)² To, = $ * 2x 10-2* [- VS -17% + 1.5 V5, +15= 10-? [Vsi ti ja = 1.5 Vsi +15 10-? Vs +5+ 2 vs,] 1500 Vs, + 15x102= Vs + 2 Vs, ¢ =D Vsi - 1498 vso - 14,999 =0 solving above eqh we get Vsi = 1507.95 + which is not valis T .-9.95v | Vas, = 9.950 cand I VONI = Vasi - Vt = 8.85v ID, = 1.5(-9195)+15 .: ID: 75 mA Vo = 10- Io, (3) ,: Voi = 9.975 V Yos,> Vas, - vt = M, in in naturation.
(6) VQ2 = VD, = 9.975V ID2=4 MA Assuming Me is in naturation, Ip, = { x kan en ) ( vasa -V)2 => 405 { * 2x10-3 *19.975 - Vsz -1]? => 4046 = (V52 + 8.925)? aa
VS2 + 8.975 = { 2 VS2 =-6.975 v 1 = VS2 = -10-975 which is smce not valid Uss = -lov. Vasz = 9.975 +6.975 VON2 = 15.950 Verse = 16.95 V Vos, = 9 +6.975 Tvosg= 15.975 v/ > Vona * M₂ is in saturation,